What mass of copper oxide (2) will be obtained by the interaction of 336 liters of oxygen with copper?

Metallic copper reacts with oxygen to form oxide. The reaction is described by the following chemical equation:

Cu + ½ O2 = CuO ↑;

Let’s calculate the chemical amount of oxygen. To do this, we divide its volume by the volume of 1 mole of gas (which is 22.4 liters).

N O2 = 336 / 22.4 = 15 mol;

With this amount of oxygen, twice the amount of copper oxide will be synthesized, which will be 15 x 2 = 30 mol of copper oxide.

Find the weight of the copper oxide. For this purpose, we multiply the amount of the substance by the weight of 1 mole of the substance.

M CuO = 64 + 16 = 80 grams / mol;

m CuO = 80 x 30 = 2400 grams = 2.4 kg;