Metallic copper reacts with oxygen to form oxide. The reaction is described by the following chemical equation:
Cu + ½ O2 = CuO ↑;
Let’s calculate the chemical amount of oxygen. To do this, we divide its volume by the volume of 1 mole of gas (which is 22.4 liters).
N O2 = 336 / 22.4 = 15 mol;
With this amount of oxygen, twice the amount of copper oxide will be synthesized, which will be 15 x 2 = 30 mol of copper oxide.
Find the weight of the copper oxide. For this purpose, we multiply the amount of the substance by the weight of 1 mole of the substance.
M CuO = 64 + 16 = 80 grams / mol;
m CuO = 80 x 30 = 2400 grams = 2.4 kg;
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