What mass of copper oxide is required in order to obtain 128 g of copper from it during reduction with hydrogen?

Divalent copper oxide is reduced with hydrogen gas when heated. This synthesizes metallic copper and water. This reaction is described by the following equation:

CuO + H2 = Cu + H2O;

Cupric oxide reacts with hydrogen in equal (equivalent) molar amounts. When this reaction proceeds, the same equal chemical amounts of copper and water are synthesized.

Let’s calculate the chemical amount of copper.

To do this, divide the weight of copper by the weight of 1 mole of metal.

M Cu = 64 grams / mol;

N Cu = 128/64 = 2 mol;

Let’s calculate the weight of this amount of copper oxide.

M CuO = 64 + 16 = 80 grams / mol;

m CuO = 80 x 2 = 160 grams;

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