What mass of copper was released from the copper (2) -sulfate solution after iron filings were dipped into the solution?

What mass of copper was released from the copper (2) -sulfate solution after iron filings were dipped into the solution? The mass of iron filings by the end of the reaction decreased by 11.2 g.

Let’s find the amount of the substance of iron filings by the formula:

n = m: M.

M (Fe) = 56 g / mol.

n = 11.2 g: 56 g / mol = 0.2 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Fe + CuSO4 = FeSO4 + Cu ↓.

According to the reaction equation, 1 mol of iron accounts for 1 mol of copper. The substances are in quantitative ratios of 1: 1.

The amount of substance will be equal.

n (Fe) = n (Cu) = 0.2 mol.

Let’s find the mass of copper.

M (Cu) = 64 g / mol.

m = n × M.

m = 64 g / mol × 0.2 mol = 12.8 g.

Answer: 12.8 g.