What mass of diethyl ether forms upon interaction 6.8 g. sodium ethylate and 11 g of bromoethane

| September 11, 2021 | education

What mass of diethyl ether forms upon interaction 6.8 g. sodium ethylate and 11 g of bromoethane, if the ether yield = 90%?

1. Let’s write down the reaction equation:

C2H5ONa + C2H5Br = C2H5-O-C2H5 + NaBr.

2. Let’s find the amount of starting substances:

n (C2H5ONa) = m (C2H5ONa) / M (C2H5ONa) = 6.8 g / 68 g / mol = 0.1 mol.

n (C2H5Br) = m (C2H5Br) / M (C2H5Br) = 11 g / 109 g / mol = 0.1 mol.

3. The equation shows that the initial substances are in equal amounts, which means we find the theoretical amount of ether for any of them:

ntheor (C2H5-O-C2H5) = n (C2H5ONa) = 0.1 mol.

nprak (C2H5-O-C2H5) = ntheor (C2H5-O-C2H5) * η (C2H5-O-C2H5) / 100% = 0.1 mol * 90% / 100% = 0.09 mol

m (C2H5-O-C2H5) = nprak (C2H5-O-C2H5) * M (C2H5-O-C2H5) = 0.09 mol * 74 g / mol = 6.66 g.

Answer: m (C2H5-O-C2H5) = 6.66 g.



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