What mass of divinyl can be obtained from 156.8 liters of ethane?

By the condition of the problem, we write the equations for the synthesis of divinyl:
C2H6 – C2H5Cl – C4H10 – C4H6;
C2H6 + Cl2 = C2H5Cl + HCl – substitution reaction, chloroethane obtained;
2С2Н5Cl + 2Na = C4H10 + 2NaCl – butane is released during the Wurtz reaction;
С4Н10 = Н2С = СН – СН = СН2 + 2Н2 – butane pyrolysis occurs with the participation of the Cr2O3 catalyst, divinyl and hydrogen are formed.
Let’s calculate the molar masses of substances:
M (C2H6) = 30 g / mol;
M (C4H6) = 54 g / mol.
Let’s determine the number of moles of ethane:
1 mol of gas at normal level – 22.4 liters.
X mol (C2H6) – 156.8 liters. hence, X mol (C2H6) = 1 * 156.8 / 22.4 = 7 mol;
Y (C4H6) = 7 mol, since according to the equations the amount of these substances is 1 mol.
We find the mass of divinyl by the formula:
m (C4H6) = Y * M = 7 * 54 = 378 g.
Answer: the mass of organic matter butadiene -1.3 (divinyl) is 378 g.