What mass of ethanal was oxidized with an ammonia solution of silver oxide if 0.3 mol of silver was released as a result?

Let’s write the reaction equation:
CH3COH + 2 [Ag (NH3) 2] OH (t) = CH3COONH4 + 2Ag + 3NH3 + H2O
According to the reaction equation, 2 mol of Ag is formed per 1 mol of CH3COH, therefore:
v (CH3COH) = v (Ag) / 2 = 0.3 / 2 = 0.15 (mol).
Thus, the mass of ethanal reacted is:
m (CH3COH) = v (CH3COH) * M (CH3COH) = 0.15 * 44 = 6.6 (g).
Answer: 6.6 g.



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