What mass of ethanol is formed by the interaction of 11 g of acetaldehyde (CH3-CHO) with hydrogen?

Let’s write the reaction equation:

CH3COH + H2 (t, cat.) = CH3CH2OH

Let’s find the amount of ethanal substance (acetaldehyde):

v (CH3COH) = m (CH3COH) / M (CH3COH) = 11/44 = 0.25 (mol).

According to the reaction equation, from 1 mol of CH3COH, 1 mol of CH3CH2OH is formed, therefore:

v (CH3CH2OH) = v (CH3COH) = 0.25 (mol).

Thus, the mass of the resulting ethanol:

m (CH3CH2OH) = v (CH3CH2OH) * M (CH3CH2OH) = 0.25 * 46 = 11.5 (g).

Answer: 11.5 g.