What mass of ethene can be obtained in the process of dehydration of 92 g of ethanol
| January 15, 2021 | education
1. Let’s write the reaction equation:
C2H5OH = C2H4 + H2O.
2. Find the amount of ethanol:
n (C2H5OH) = m (C2H5OH) / M (C2H5OH) = 92 g / 46 g / mol = 2 mol.
3. According to the equation, we find the amount and then the mass of ethylene:
n (C2H4) = n (C2H5OH) = 2 mol.
m (C2H4) = n (C2H4) * M (C2H4) = 2 mol * 28 g / mol = 56 g.
Answer: m (C2H4) = 56 g.
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