What mass of ethyl acetate can be obtained by esterification of ethanol with a mass of 3.22 g

What mass of ethyl acetate can be obtained by esterification of ethanol with a mass of 3.22 g and acetic acid with a mass of 3.6 g if the mass fraction of the ether yield is 75%?

Given:
m (C2H5OH) = 3.22 g
m (CH3COOH) = 3.6 g
η (CH3COOC2H5) = 75%

To find:
m pract. (CH3COOC2H5) -?

1) C2H5OH + CH3COOH => CH3COOC2H5 + H2O;
2) n (C2H5OH) = m / M = 3.22 / 46 = 0.07 mol;
3) n (CH3COOH) = m / M = 3.60 / 60 = 0.06 mol;
4) n theory. (CH3COOC2H5) = n (CH3COOH) = 0.06 mol;
5) n practical (CH3COOC2H5) = η * n theory. / 100% = 75% * 0.06 / 100% = 0.045 mol;
6) m practical. (CH3COOC2H5) = n practical. * M = 0.045 * 88 = 3.96 g.

Answer: The practical mass of CH3COOC2H5 will be 3.96 g.