What mass of ethyl alcohol should be taken to obtain 10 liters of ethylene?

1. Let’s write down the reaction equation:

C2H5OH = C2H4 + H2O.

2. Find the amount of ethylene (Vm – molar volume, constant equal to 22.4 l / mol):

n (C2H4) = V (C2H4) / Vm = 10 L / 22.4 L / mol = 0.446 mol.

3. According to the reaction equation, we find the amount, and then the mass of alcohol:

n (C2H5OH) = n (C2H4) = 0.446 mol.

m (C2H5OH) = n (C2H5OH) * M (C2H5OH) = 0.446 mol * 46 g / mol = 20.54 g.

Answer: m (C2H5OH) = 20.54 g.



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