What mass of ethyl ester of acetic acid at 80% yield can be obtained from 5 g of alcohol?

Let’s implement the solution:

In accordance with the condition of the problem, we will write the data:

CH3COOH + C2H5OH = CH3COO – C2H5 + H2O – esterification, ethyl acetate was obtained.

We make calculations using the formulas:
M (C2H5OH) = 46 g / mol;

M (next ether) = 88 g / mol;

Y (C2H5OH) = m / M = 5/46 = 0.1 mol;

Y (ester) = 0.1 mol since the amount of substances is 1 mol.

Find the mass of the product:
m (sl. ether) = Y * M = 0.1 * 88 = 8.8 g

Answer: the mass of ethyl acetate is 8.8 g