What mass of ethylene and water is needed to obtain 12 mol of alcohol.

univerkov | September 21, 2021 | education

Given:
n (alcohol) = 12 mol

Find:
m (C2H4) -?
m (H2O) -?

1) C2H4 + H2O => C2H5OH;
2) n (C2H4) = n (C2H5OH) = 12 mol;
3) m (C2H4) = n * M = 12 * 28 = 336 g;
4) n (H2O) = n (C2H5OH) = 12 mol;
5) m (H2O) = n * M = 12 * 18 = 216 g.

Answer: The mass of C2H4 is 336 g; H2O – 216 g.

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