Let’s write the reaction equation:
3Fe + 2O2 (t) = Fe3O4
Let’s find the amount of iron substance:
v (Fe) = m (Fe) / M (Fe) = 112/56 = 2 (mol).
According to the reaction equation, 1 mol of Fe3O4 is formed per 3 mol of Fe, therefore:
v (Fe3O4) = v (Fe) / 3 = 2/3 (mol).
Thus, you can get iron scale with a mass:
m (Fe3O4) = v (Fe3O4) * M (Fe3O4) = (2/3) * 232 = 154. (6) = 154.7 (g).
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