What mass of Fe3O4 can be obtained as a result of interaction with iron oxygen weighing 112g?

Let’s write the reaction equation:

3Fe + 2O2 (t) = Fe3O4

Let’s find the amount of iron substance:

v (Fe) = m (Fe) / M (Fe) = 112/56 = 2 (mol).

According to the reaction equation, 1 mol of Fe3O4 is formed per 3 mol of Fe, therefore:

v (Fe3O4) = v (Fe) / 3 = 2/3 (mol).

Thus, you can get iron scale with a mass:

m (Fe3O4) = v (Fe3O4) * M (Fe3O4) = (2/3) * 232 = 154. (6) = 154.7 (g).

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