What mass of gas is released when 200 grams of calcium carbonate interacts with hydrochloric acid?

Given:

m (CaCO3) = 200 g

To find:

m (gas) -?

Solution:

CaCO3 + 2HCl = CaCl2 + H2O + CO2, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of calcium carbonate that has reacted:

n (CaCO3) = m: M = 200 g: 100 g / mol = 2 mol

2) We compose a logical expression:

if 1 mol of CO2 requires 1 mol of CaCO3,

then x mol of CO2 will require 2 mol of CaCO3,

then x = 2 mol.

3) Find the mass of carbon dioxide released as a result of the reaction:

m (CO2) = n * M = 2 mol * 44 g / mol = 88 g.

Answer: m (CO2) = 88 g.