What mass of gluconic acid is formed during the oxidation of 40 g of glucose?

In accordance with the condition of the problem, we write down the reaction equation:
C6H12O6 + Ag2O = C6H12O7 + 2Ag – the oxidation reaction of glucose with silver oxide, gluconic acid and silver were obtained;
Let’s make calculations using the formulas of substances:
M (C6H12O6) = 12 * 6 + 1 * 12 + 16 * 6 = 180 g / mol;
M (C6H12O7) = 12 * 6 + 1 * 12 + 16 * 7 = 196 g / mol;
Let’s calculate the number of moles of glucose if the mass is known:
Y (C6H12O6) = m / M = 40/180 = 0.22 mol;
Let’s make the proportion:
0.2 mol (C6H12O6) – X mol (C6H12O7);
-1 mol -1 mol hence, X mol (C6H12O7) = 0.2 * 1/1 = 0.2 mol;
Determine the mass of gluconic acid by the formula:
m (C6H12O7) = Y * M = 0.22 * 196 = 43.12 g.
Answer: in this reaction, gluconic acid with a mass of 43.12 g is released.