What mass of glucose can be obtained by hydrolysis of 5 mol of sucrose?

Let’s implement the solution:
Y = 5 mol X g -?

C12H22O11 + H2O = C6H12O6 (glucose) + C6H12O6 (fructose) – hydrolysis, glucose was formed;

Calculations by the formulas of organic compounds:
M (C6H12O6) = 180 g / mol;

Y (C12H22O11) = 5 mol;

Y (C6H12O6) = 5 mol since the amount of substances is equal to 1 mol.

Find the mass of the product:
m (C6H12O6) = Y * M = 5 * 180 = 900 g
Answer: received glucose weighing 900 g