What mass of glucose can be obtained from 100 kg of potatoes containing 22% starch if the glucose yield is 75%

Let’s find the mass of starch in the potato.

100 kg – 100%,

X kg – 22%,

X = (22% × 100 kg): 100% = 22 kg.

Let’s compose the reaction equation for obtaining glucose from starch.

(C6H10O5) n → C6H12O6.

М (С6Н10О5) n) = 162 n kg / kmol.

М (С6Н12О6) n = 180 n kg / kmol.

n = 22 kg: 162 n kg / kmol = 0.1358 n kmol.

Let’s make a proportion.

22 kg / 162 n = x (kg of glucose) / 180 n.

X = (22 × 180 n): 162 n,

X = 24.44 g.

24.44 received glucose as calculated.

In theory, the glucose yield was 75%.

24.44 kg – 100%,

X – 75%,

X = (24.44 kg × 75%): 100% = 18.33%.

Answer: 18.33%.