What mass of h2o is needed for hydrolysis of 16.6 g of sucrose?

Let’s implement the solution:
1. In accordance with the condition, we write down the process:
m = 16.6 g. X g. -?
С12Н22О11 + Н2О (H2SO4) = C6H12O6 (glucose) + С6Н12О6 (fructose) – acid hydrolysis, glucose is formed. Fructose;
2. Calculations according to the formulas of substances:
M (C12H22O11) = 342 g / mol.
M (H2O) = 18 g / mol.
Y (C12H22O11) = m / M = 16.6 / 342 = 20.6 mol.
Y (H2O) = 20.6 mol since the amount of substances according to the equation is 1 mol.
3. Find the mass of the original substance:
m (H2O) = Y * M = 20.6 * 18 = 370.8 g.
Answer: you need water weighing 370.8 g.