What mass of hydrogen is formed by the interaction of 13 g of zinc with phosphoric acid?
| April 30, 2021 | education
1. Let’s write down the reaction equation:
3Zn + 2H3PO4 = Zn3 (PO4) 2 + 3H2.
2. Find the amount of zinc:
n (Zn) = m (Zn) / M (Zn) = 13 g / 65 g / mol = 0.2 mol.
3. According to the reaction equation, we find the amount and then the mass of the released hydrogen:
n (H2) = n (Zn) = 0.2 mol.
m ((H2) = n (H2) * M (H2) = 0.2 mol * 2 g / mol = 0.4 g.
Answer: m ((H2) = 0.4 g.
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