What mass of hydrogen is formed by the interaction of zinc weighing 12 g

What mass of hydrogen is formed by the interaction of zinc weighing 12 g h with an excess of dilute sulfuric acid, if the yield of the reaction product is 98%.

1. Let’s write the equation of the reaction of zinc with dilute sulfuric acid:

Zn + H2SO4 = ZnSO4 + H2 ↑.

2. Let’s calculate the chemical amount of zinc:

n (Zn) = m (Zn): M (Zn) = 12: 65 = 0.1846 mol.

3. Determine the theoretical amount of released hydrogen:

ntheor (H2) = n (Zn) = 0.1846 mol.

4. Let us establish the practical amount of hydrogen, taking into account the values of the product yield:

npract (H2) = ntheor (H2) * ν = 0.1846 * 0.98 = 0.1809 mol.

5. Let’s calculate the mass of hydrogen:

m (H2) = npract (H2) * M (H2) = 0.1809 * 2 = 0.3618 g.

Answer: 0.3618 g.