What mass of hydrogen is formed by the reaction of 6.02 * 10 ^ 22 zinc atoms with sulfuric acid?

First, we write down the equation of reactions.
Zn + H2S04 = ZnSO4 + H2.
Find the amount of substance Zn using the following formula.
n = N / NA.
Where NA is a constant of 6.02 × 10 ^ 23 mol ^ -1.
n = 6.02 × 10 ^ 22 / 6.02 × 10 ^ 23 = 1/10 = 0.1 mol.
Further, according to the reaction equation, we find the amount of hydrogen substance.
0.1 mol Zn – x mol H2
1 mol Zn – 1 mol H2
X = 0.1 × 1 ÷ 1 = 0.1 mol H2.
Next, we find the mass of hydrogen using the following formula.
n = m / M.
m = n M.
m = 0.1 mol × 2 g / mol = 0.2 g H2.
Answer: m (H2) = 0.2 g.