What mass of hydrogen will be added to butene if you get 320 g of butane?
| January 8, 2021 | education
1. Let’s write the reaction equation:
C4H8 + H2 = C4H10.
2. Find the amount of butane:
n (C4H10) = m (C4H10) / M (C4H10) = 320 g / 58 g / mol = 5.52 mol.
3. Using the reaction equation, we find the amount of hydrogen, and then its mass:
n (H2) = n (C4H10) = 5.52 mol.
m (H2) = n (H2) * M (H2) = 5.52 mol * 2 g / mol = 10.04 g.
Answer: m (H2) = 10.04 g.
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