What mass of ice taken at -20 degrees Celsius can be turned into water at 20 degrees Celsius

What mass of ice taken at -20 degrees Celsius can be turned into water at 20 degrees Celsius to burn 100 grams of gasoline?

q * m = Q1 + Q2 + Q3.

Q = q * m, q – beats. heat of combustion of gasoline (q = 44 MJ = 44 * 106 J / kg), m is the mass of gasoline (m = 0.1 kg)).

Q1 = C1 * m1 * (tк – tн), C1 – beats. warm ice (C1 = 2100 J / (K * kg)), m1 – ice mass, tc = 0 ºС, tн = -20 ºС.

Q2 = λ * m1, λ – beats. heat of melting of ice (λ = 340 * 10³ J / kg).

Q3 = C2 * m1 * (tк – tн), where C2 – beats. warm water (С = 4200 J / (K * kg)), tк = 20 ºС, tн = 0 ºС.

m1 = 44 * 106 * 0.1 / (2100 * 20 + 340 * 10³ + 4200 * 20) = 9.44 kg.



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