What mass of ice taken at a temperature of 0 degrees C will melt if it is told the same amount

What mass of ice taken at a temperature of 0 degrees C will melt if it is told the same amount of heat that will be released during the condensation of centigrade water vapor weighing 8 kg.

Given:
t1 = 0 ° C,
t2 = 100 ° C,
m2 = 8kg,
λ = 3.4 * 10 ^ 5 J / kg – specific heat of ice melting,
r = 2.26 * 10 ^ 6 J / kg is the specific heat of vaporization of water;
Find: m1 -?
Since ice is at a temperature of 0 ° C, the amount of heat for melting it is equal to
Q1 = λ * m1;
And the amount of heat that is released during condensation of steam at a temperature of 100 ° C is
Q2 = r * m2;
By the condition of the problem:
Q1 = Q2;
λ * m1 = r * m2;
m1 = r * m2 / λ = 2.26 * 10 ^ 6 * 8 / (3.4 * 10 ^ 5) = 53.18kg.