What mass of iron can be obtained by reducing 80 g of iron (3) oxide with hydrogen?

Fe2O3 + 3H2 = 2Fe + 3H2O

Let us find the amount of the substance of iron oxide (3) = m: M = 80: 160 = 0.5 mol

Find the amount of iron substance by the coefficients of the equation = 2/1 * 0.5 = 1 mol

Find the mass of iron: m = M * amount of substance = 56 * 1 = 56 grams



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