What mass of iron can be obtained by reduction of 464 g of Fe3O4 with carbon monoxide if the yield of the reaction product is 85%?

univerkov | December 3, 2020 | education

Fe3O4 + 4CO = 3Fe + 4CO2
n (Fe3O4) = m \ M = 464 \ 232 = 2 mol
for ur-th p-and n (Fe) = 2 * 3 = 6 mol
m (Fe) theory = nM = 6 * 56 = 336 g
m (practical) = output * m (theory) = 0.85 * 336 = 285.6 g
Answer: 285.6 g

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