What mass of iron can be obtained from 128 kg of iron oxide 3
| June 19, 2021 | education
1. Let’s write down the reaction equation:
2Fe2O3 + 3C = 2Fe + 3CO2.
2. Find the amount of iron oxide:
128 kg = 128000 g.
n (Fe2O3) = m (Fe2O3) / M (Fe2O3) = 128000 g / 160 g / mol = 800 mol.
3. According to the reaction equation, we find the amount, and then the mass of iron:
n (Fe) = n (Fe2O3) = 800 mol.
m (Fe) = n (Fe) * M (Fe) = 800 mol * 56 g / mol = 44800 g = 44.8 kg.
Answer: m (Fe) = 44.8 kg.
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