What mass of iron III chloride was formed if 18 g of chlorine reacted with iron?
| May 26, 2021 | education
1. We make a chemical equation, not forgetting to put down the coefficients:
2Fe + 3Cl2 = 2FeCl3.
2. Find the amount of substance Cl:
n (Cl2) = 18g / 71g = 0.25 mol.
3. Find the amount of the substance FeCl3:
n (FeCl3) = n (Cl2) * 2/3 = 0.17 mol.
4. Find the mass of FeCl3:
m (FeCl3) = n * M = 0.17 * (56 + 35.5 * 3) = 28g.
Answer: m (FeCl3) = 28g.
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