What mass of iron sulfide FeS was obtained by the interaction of 28 g of iron with sulfur?

We find what mass of iron sulfide FeS was obtained by the interaction of 28 g of iron with sulfur.
We write the following reaction equation.

28 g x g
Fe + S = FeS
n = 1 mol n = 1 mol
We consider the molar mass of iron and the molar mass of iron sulfide.
M (Fe) = 56 g / mol;
M (FeS) = 60 g / mol.

m = 56 g m = 60 g
We make the following proportion.

28 g Fe – X g FeS;
56 g Fe – 60 g FeS.
We multiply crosswise.
28 g × 60 g FeS = 56 g Fe × x g FeS.
We express the mass of FeS.
m (FeS) = 28 * 60/56 = 30 g;
Consequently, the mass of the formed iron sulfide is 30 grams.
Answer: m (FeS) = 30 g.