What mass of iron will be obtained as a result of alumetry 3 mol of iron oxide (3) if the mass fraction of the yield is 90%.

1. Let’s write down the reaction equation:

Fe2O3 + 2Al = 2Fe + Al2O3.

2. According to the reaction equation, we find the theoretical amount of iron obtained:

ntheor (Fe) = 0.5n (Fe2O3) = 0.5 * 3 mol = 1.5 mol.

nprak (Fe) = ntheor (Fe) * η (Fe) * 100% = 1.5 mol * 90% / 100% = 1.35 mol.

m (Fe) = nprak (Fe) * M (Fe) = 1.35 mol * 56 g / mol = 75.6 g.

Answer: m (Fe) = 75.6 g.



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