What mass of iron will be obtained from iron oxide III weighing 96 grams? When reducing it with hydrogen.

To solve the problem, we write down the reaction equation, arrange the coefficients:
Fe2O3 + 3H2 = 2Fe + 3H2O – redox reaction, iron is obtained;
M (Fe2O3) = 215.4 g / mol;
M (Fe) = 55.8 g / mol;
Determine the amount of moles of iron oxide, if the mass is known:
Y (Fe2O3) = m / m = 96 / 215.4 = 0.445 mol;
Let’s make the proportion:
0.445 mol (Fe2O3) – X mol (Fe);
-1 mol                        -2 mol from here, X mol (Fe) = 0.445 * 2/1 = 0.891 mol;
Let’s calculate the mass of iron:
m (Fe) = Y * M = 0.891 * 55.8 = 49.71 g.
Answer: the mass of iron is 49.71 g.