What mass of iron will be obtained when 80 g of iron (III) oxide is reduced with hydrogen, if the yield is 98%

What mass of iron will be obtained when 80 g of iron (III) oxide is reduced with hydrogen, if the yield is 98% of the theoretical?

Fe2O3 + 3H2 = 2Fe + 3H2O.
1) Find the molar mass of iron oxide according to the periodic table: 56 * 2 + 16 * 3 = 160.
2) Find the amount of iron oxide substance. To do this, divide the mass of the oxide by the molar mass: 80/160 = 0.5 mol.
3) According to the reaction equation, there are two moles of iron per mole of oxide. This means that the amount of iron substance is: 0.5 / 2 = 0.25 mol.
4) Find the theoretical mass of iron. To do this, we multiply the molar mass of iron by its amount of substance: 0.25 * 56 = 14g.
5) Practical weight of iron: 98 * 14/100 = 13.72 g – the answer.