What mass of magnesium carbonate is required to interact with a 420 ml hydrochloric acid solution with

What mass of magnesium carbonate is required to interact with a 420 ml hydrochloric acid solution with a mass fraction of HCl 10% (p = 1.05 g / ml)? How much gas will be released as a result of the reaction?

Magnesium carbonate reacts with hydrochloric acid. In this case, magnesium chloride is synthesized and gaseous carbon dioxide is released. The reaction is described by the following equation:

MgCO3 + 2HCl = MgCl2 + H2O + CO2 ↑;

Let’s calculate the chemical amount of hydrochloric acid.

To do this, divide the weight of the acid by the weight of 1 mole of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 420 x 1.05 x 0.1 / 36.5 = 1.208 mol;

With this amount of acid, 1.208 / 2 = 0.604 mol of magnesium carbonate will react.

Let’s calculate its weight.

To do this, multiply its molar weight by the amount of substance.

M MgCO3 = 24 + 12 + 16 x 3 = 84 grams / mol;

m MgCO3 = 84 x 0.604 = 50.736 grams;