What mass of magnesium chloride is obtained if 36 g of magnesium reacts with chlorine?

Mg + Cl2 = MgCl2

We recognize the molar masses of magnesium and magnesium chloride from the periodic table:

M (Mg) = 24 g / mol; M (MgCl2) = 95 g / mol

Find out the amount of magnesium substance

n = m / M

n (Mg) = 36g / 24 g / mol

n (Mg) = 1.5 mol.

According to the equation n (Mg) = n (MgCl2) = 1.5 mol.

Find out the mass of the obtained magnesium chloride

m = n * M

m (MgCl2) = 1.5 mol * 95 g / mol

m (MgCl2) = 142.5 g.

Answer: 142.5 grams is the mass of the obtained magnesium chloride.