What mass of magnesium hydroxide is formed when a solution of magnesium chloride with sodium hydroxide weighing 8 g is affected?

univerkov | January 17, 2021 | education

Given:
m (NaOH) = 8 g
To find:
m (Mg (OH) 2)
Decision:
MgCl2 + 2NaOH = 2NaCl + Mg (OH) 2
n (NaOH) = 8/40 = 0.2 mol
n (NaOH): n (Mg (OH) 2) = 2: 1
n (Mg (OH) 2) = 0.2 / 2 = 0.1 mol
m (Mg (OH) 2) = 0.1 * 58 = 5.8 g
Answer: 5.8 g

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