What mass of methanal can be obtained by oxidation of 0.2 mol of methanol?

univerkov | November 19, 2020 | education

CH3OH + CuO -> HCOH + Cu + H2O n (CH3OH) = 0.2 mol n (CH3OH) = n (HCOH) = 0.2 mol (1: 1) m (HCOH) = n • m = 0.2 mol • 30 g / mol = 6 g Answer: m (HCOH) = 6 g.

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