What mass of methanol can be obtained from formaldehyde with a mass of 45 g, if the mass fraction of the yield is 95%?

According to the condition of the problem, we compose the reaction equation:
НСОН + Н2 = СН3 – ОН – hydrogenation reaction, methanol was obtained;
M (CH2O) = 30 g / mol;
M (CH3OH) = 32 g / mol;
Determine the amount of mol of formaldehyde:
Y (CH2O) = m / M = 45/30 = 1.5 mol;
Let’s make a proportion according to the equation:
1.5 mol (CH2O) – X mol (CH3OH);
1 mol -1 mol hence, X mol (CH3OH) = 1.5 * 1/1 = 1.5 mol;
Let’s calculate the mass of methanol (theoretical):
m (theoretical) = Y * M = 1.5 * 32 = 48 g.
Determine the mass of methanol (practical), if the mass fraction of the output is 95%:
W = m (practical) / m (theoretical) * 100;
m (practical) = 0.95 * 48 = 45.6 g.
Answer: the mass of methanol is 45.6 g.