What mass of methanol entered into the oxidation reaction if 11.2 liters of methanal were formed?

Solution:
Let’s write the reaction equation:
CH3 – OH + CuO = HCOH + Cu + H2O – methanol oxidation reaction, methanal was obtained;
M (CH3OH) = 32 g / mol;
Determine the number of moles of methanal, if 1 mol (CH2O) – 22.4 liters;
X mol – 11.2 liters.
X mol (CH2O) = 11.2 * 1 / 22.4 = 0.5 mol;
Determine the number of moles of methanol based on the proportion:
X mol (CH3OH) – 0.5 mol (CH2O);
-1 mol – 1 mol hence, X mol (CH3OH) = 0.5 mol;
Let’s calculate the mass of methanol by the formula: m (CH3OH) = Y (CH3OH) * M (CH3OH);
m (CH3OH) = 0.5 * 32 = 16 g.
Answer: methanol reacted with a mass of 16 g.