What mass of methanol underwent oxidation with copper (II) oxide if 0.5 mol of copper was

What mass of methanol underwent oxidation with copper (II) oxide if 0.5 mol of copper was formed as a result of the reaction?

Based on the data of the problem, we write down the equation of the oxidation process:
CH3OH + CuO = HCOH + Cu + H2O – methanal and copper are released;

Let’s make the calculations:
M (CH3OH) = 32 g / mol;

M (Cu) = 63.5 g / mol.

Determine the amount of the original substance:
Y (Cu) = 0.5 mol; Y (CH3OH) = 0.5 mol since the amount of substances is 1 mol.

We find the mass of alcohol:
m (CH3OH) = Y * M = 0.5 * 32 = 16 g

Answer: you need methyl alcohol weighing 16 g