What mass of methyl acetate can be obtained from methanol with a mass of 16 g and acetic

What mass of methyl acetate can be obtained from methanol with a mass of 16 g and acetic acid with a mass of 27 g. Mass fraction of the ether yield is 75%.

CH3OH + CH3COOH = CH3COO – CH3 + H2O – esterification, methyl acetate was formed;
Calculations by formulas:
M (CH3OH) = 32 g / mol;

M (CH3COOH) = 60 g / mol.

3. Let us determine the amount of starting substances, if the mass is known:

Y (CH3OH) = m / M = 16/32 = 0.5 mol (substance in excess);

Y (CH3COOH) = m / M = 27/60 = 0.45 mol (deficient substance).

Y (methyl acetate) = 0.45 mol since the amount of substances is 1 mol.

Calculations are made for the substance in deficiency.

4. Determine the mass of ether, taking into account the yield of the product:

m (methyl acetate) = Y * M = 0.45 * 74 = 33.3 g (theoretical weight);

m (methyl acetate) = 0.75 * 33.3 = 24.98 g (practical weight).

Answer: an ester (methyl acetate) weighing 24.98 g was obtained

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.