What mass of methyl acetate is formed by the interaction of 80 g of a 60% solution of acetic acid with methyl alcohol

| November 19, 2020 | education

What mass of methyl acetate is formed by the interaction of 80 g of a 60% solution of acetic acid with methyl alcohol, if the fraction of the ester yield is 90%?

Equation for obtaining methyl acetate:
CH3COOH + CH3OH = CH3COOCH3 + H2O.
Find the mass of the acetic acid that has reacted:
m (CH3COOH) = m * W / Wm = 80 * 60/100 = 48 g.
Let’s calculate the number of moles:
n (CH3COOH) = m / Mr = 48/60 = 0.8 mol.
It can be seen from the equation of the reaction that the amount of moles of starting substances and products is the same:
n (CH3COOCH3) = n (CH3COOH) = 0.8 mol.
Let’s find the theoretical mass of the ether:
m (CH3COOCH3) = n * Mr = 0.8 * 74 = 59.2 g
Let’s find the practical mass of ether:
m (CH3COOCH3) = m (theory) * W / 100% = 59.2 * 90/100 = 53.3 g.



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