What mass of nitric acid is required to completely neutralize 1.71 g of barium hydroxide.

univerkov | November 17, 2020 | education

2HNO3 + Ba (OH) 2 = Ba (NO3) 2 + 2 H2O
n (BaOH) = 1.71 g / 171 g / mol = 0.01 mol
n (HNO3) = 2n (Ba (OH) 2 = 0.02 mol
m (HNO3) = 0.02 mol * 63g / mol = 1.26 g

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