What mass of nitric acid is required to dissolve 11.76 g of copper (II) hydroxide if the reaction

What mass of nitric acid is required to dissolve 11.76 g of copper (II) hydroxide if the reaction products are copper (II) nitrate and water?

Given:
m (Cu (OH) 2) = 11.76 g

Find:
m (HNO3) -?

1) 2HNO3 + Cu (OH) 2 => Cu (NO3) 2 + 2H2O;
2) n (Cu (OH) 2) = m / M = 11.76 / 98 = 0.12 mol;
3) n (HNO3) = n (Cu (OH) 2) * 2 = 0.12 * 2 = 0.24 mol;
4) m (HNO3) = n * M = 0.24 * 63 = 15.12 g.

Answer: The mass of HNO3 is 15.12 g.