What mass of nitric acid is required to neutralize 80 g of potassium hydroxide with a mass fraction of 40%?

univerkov | December 3, 2020 | education

KOH + HNO3 = H2O + KNO3
m (KOH) = w * m (solution) = 0.4 * 80 = 32 g
n (KOH) = m \ M = 32 \ 56 = 0.57 mol
n (HNO3) = n (KOH) = 0.57 mol at ur-th p-i
m (HNO3) = nM = 0.57 * 63 = 35.91 g
Answer: 35.91 g

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.