What mass of nitric acid will react with 3 mol of naoh?

n (NaOH) = 3 mol
To find:
m (HNO3)
NaOH + HNO3 = H2O + NaNO3
n (NaOH): n (HNO3) = 1: 1
n (HNO3) = 3 mol
m (HNO3) = n * M = 3 mol * 63 g / mol = 189 g
Answer: 189 g

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