What mass of nitromethane is formed from 30 grams of nitric acid?

Given:
m (HNO3) = 30 g
To find:
m (CH3-NO2)
Decision:
CH4 + HNO3 = CH3-NO2 + H2O
n (HNO3) = m / M = 30 g / 63 g / mol = 0.476 mol
n (HNO3): n (CH3-NO2) = 1: 1
n (CH3-NO2) = 0.476 mol
m (CH3-NO2) = n * M = 0.476 mol * 61 g / mol = 29 g
Answer: 29 g



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