What mass of oxygen was obtained during the photosynthesis reaction if 90 g of glucose were formed?
| February 19, 2021 | education
1. Let’s write down the reaction equation:
6CO2 + 6H2O = C6H12O6 + 6O2.
2. Find the amount of glucose:
n (C6H12O6) = m (C6H12O6) / M (C6H12O6) = 90 g / 180 g / mol = 0.5 mol.
3. According to the reaction equation, we find the amount, and then the mass of oxygen:
6n (O2) = n (C6H12O6).
n (O2) = n (C6H12O6) / 6 = 0.5 mol / 6 = 0.083 mol.
m (O2) = n (O2) * M (O2) = 0.083 mol * 32 g / mol = 2.67 g.
Answer: m (O2) = 2.67 g.
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