What mass of phosphorus oxide (v) is formed during the combustion of 62 g of phosphorus?
| September 14, 2021 | education
1. We make a chemical equation, not forgetting to put down the coefficients:
4P + 5O2 = 2P2O5.
2. Let’s find the amount of phosphorus substance:
n (P) = m / M = 62/31 = 2 mol.
3. From the equation you can see:
n (P) / n (P2O5) = 2/1; Therefore: n (P2O5) = 1 mol.
4. Find the mass of phosphorus oxide (V):
m (P2O5) = Mr * 1 = 142 * 1 = 142g.
Answer: m (P2O5) = 142g.
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