What mass of potassium hydroxide is formed by the interaction with water of 4.7 grams of potassium oxide?

1. We make a chemical equation, not forgetting to put down the coefficients:

K2O + H2O = 2KOH.

2. Find the amount of substance K2O:

n (K2O) = m / М = 4.7g / 94 g / mol = 0.05 mol.

3. Find the amount of substance KOH:

n (KOH) = 0.05 * 2 = 0.1 mol.

4. Find the mass of KOH:

m (KOH) = n * M = 0.1 mol * 56 g / mol = 5.6 g.

Answer: m (KOH) = 5.6g (3).



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