What mass of potassium hydroxide will be obtained if you combine solutions of barium hydroxide

What mass of potassium hydroxide will be obtained if you combine solutions of barium hydroxide and potassium sulfate weighing 120 g containing 10% sulfate?

1. Let’s write down the reaction equation:

Ba (OH) 2 + K2SO4 = BaSO4 + 2KOH.

2. Find the amount of potassium sulfate:

m (K2SO4) = m (solution) * ω (K2SO4) / 100% = 120 g * 10% / 100% = 12 g.

n (K2SO4) = m (K2SO4) / M (K2SO4) = 12 g / 135 g / mol = 0.089 mol.

3. According to the reaction equation, we find the amount of potassium hydroxide, and then its mass:

n (KOH) = n (K2SO4) * 2 = 0.089 mol * 2 = 0.18 mol.

m (KOH) = n (KOH) * M (KOH) = 0.18 mol * 56 g / mol = 9.96 g.

Answer: m (KOH) = 9.96 g.